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--- project:sprinklers [2024-04-17 Wed wk16 13:11] – [Sprinkler Solenoid 24VAC Woes] baumkp
+++ project:sprinklers [2024-04-17 Wed wk16 13:21] – [Sprinkler Solenoid 24VAC Woes] baumkp
@@ Line 32: / Line 32: @@
   - New solenoid valves are dual rated for 50/60Hz and significantly relies upon the solenoid reactance. The reactance is directly proportional to the frequency that affects the operating solenoid current and power draw.  In 50Hz applications the current and power draw are higher and hence the solenoid has less tolerance to over rated voltage.  Hopefully the resistor will solve this problem.
   - I suspect the new solenoid valves are actually optimised for 60Hz operation not 50Hz and this has been the root cause of the new valve solenoid problems I have been having.
-  - A readily available 12 Ω, 1 W resistor at cost of less than $1.00 seems to be a simple solution to rectify the solenoid failure problem.
+  - A readily available 12 Ω, 1 W resistor at cost of less than $1.00 is a simple solution to rectify the solenoid failure problem.
 Some additional comments:
@@ Line 38: / Line 38: @@
   - Avoid the use of single sprinkler wiring in more complex larger sprinkler reticulation systems.  The use of quality multi core cabling provided a much more reliable system.
   - I do not like jar top style valves, just a personal preference though.
-  - An inductor instead of a resistor may be a more effective solution to reduce the solenoid current and overall real power consumption, however resistors are cheaper and easier to get and also smaller.  The resistor power loss is < 1W, where as an inductor would probably reduce this by a factor in the order of 2 - 5.  Suitable 10mH inductors are available for purchase, e.g. [[https://au.mouser.com/ProductDetail/Murata-Power-Solutions/1410604C?qs=5CKLVr1iF0kSPSRQWGAVyQ%3D%3D|Mouser muRata Power Solutions 1410604C ]], which is rated at 10mH, 4.34 Ω & 0.4 Amps, ±10%.  However they are more expensive and larger than simple resistors.  They also need to be ordered in instead of being readily available from the local electronics store.
+  - An inductor instead of a resistor may be a more effective solution to reduce the solenoid current and overall real power consumption, however resistors are cheaper and easier to get and also smaller.  The resistor power loss is < 1W, where as an inductor would probably reduce this by a factor in the order of 2 - 5.  Suitable 10 mH inductors are available for purchase, e.g. [[https://au.mouser.com/ProductDetail/Murata-Power-Solutions/1410604C?qs=5CKLVr1iF0kSPSRQWGAVyQ%3D%3D|Mouser muRata Power Solutions 1410604C ]], which is rated at 10 mH, 4.34 Ω & 0.4 Amps, ±10%.  However they are more expensive and larger than simple resistors.  They also need to be ordered in instead of being readily available from the local electronics store.
+After 8 weeks of reliable operation with no further solenoid failure the use of a 12 Ω resistor to limit solenoid current and power draw has rectified the solenoid failure problem.  It appears the use of valve solenoids specified for dual 50/60 Hz use on 24 VAC are prone to failure with use on 50Hz supplies with voltage at solenoids greater than 24.0 VAC.
 ====References====
   *[[https://www.electronics-tutorials.ws/accircuits/power-triangle.html|Power Triangle and Power Factor]]